How to print __LINE__ and timestamp in Python log

import inspect

import datetime

import time

def log(filename):

   import os

   if not os.path.exists('Log') or not os.path.isdir('Log'):

      os.mkdir('Log')

   f = open('Log/%s.log'%filename, 'w')

   return f

def PrintMsg(msg):

    timestamp = _gettime()

    msg = '%s %5s --> ## %s' %(timestamp(), inspect.getouterframes(inspect.currentframe())[1][2], msg)

    print msg

def PrintLog(fp, msg, flag=None):

    ''' Use to print log for each task. We can use some flag to add extra

    information to the output message.

   "inspect.getouterframes(inspect.currentframe())[1][2]" can't be put

   in a nested subcall, otherwise the __LINE__ will be the nested subcall's

   call line.

   '''

   timestamp = _gettime()

   if not flag:

      printlog(fp, msg)

   elif flag == 'DT':

      msg = '%s %5d --> Download Task :: %s' %(timestamp(),  inspect.getouterframes(inspect.currentframe())[1][2], msg)

   elif flag == 'MT':

       msg = '%s %5d --> Main Task :: %s' %(timestamp(), inspect.getouterframes(inspect.currentframe())[1][2], msg)

   elif flag == 'ST':

      msg = '%s %5d --> SrchPort Task :: %s' %(timestamp(), inspect.getouterframes(inspect.currentframe())[1][2], msg)

   elif flag == 'CT':

      msg = '%s %5d --> Command Task :: %s' %(timestamp(), inspect.getouterframes(inspect.currentframe())[1][2], msg)

   else:

      pass

   _print_log(fp, msg)

def _gettime():

   '''To get the timestamp. 'lambda' is a perfect way to do this kind of job.

   '''

   return lambda: datetime.datetime.fromtimestamp(time.time())

if __name__ == '__main__':

   _msg = 'hello devan'

   f = open('testtttt.log', 'a')

   PrintMsg(_msg)

   PrintLog(f, _msg, 'DT')